200t^2-648=0

Solution for 200t^2-648=0 equation:

200t^2-648=0

a = 200; b = 0; c = -648;
Δ = b2-4ac
Δ = 02-4·200·(-648)
Δ = 518400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{518400}=720$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-720}{2*200}=\frac{-720}{400}
=-1+4/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+720}{2*200}=\frac{720}{400}
=1+4/5
$